25p^2-10p=2

Solution for 25p^2-10p=2 equation:

25p^2-10p=2

We move all terms to the left:

25p^2-10p-(2)=0

a = 25; b = -10; c = -2;
Δ = b2-4ac
Δ = -102-4·25·(-2)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{3}}{2*25}=\frac{10-10\sqrt{3}}{50}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{3}}{2*25}=\frac{10+10\sqrt{3}}{50}
$